12 May 2009

Thinking questions for rates

Filed under: 8-12,algebra,education,math — admin @ 11:01 am

Let’s suppose you are working on problems involving distance, speed and time. You might consider posing these problems one at a time.
Q1: Suppose I travel 2 hours at 40 mph and then 2 hours at 20 mph. What is my average speed for the trip?
Q2: Suppose I travel 2 hours at 40 mph and then 4 hours at 20 mph. What is my average speed for the trip?
Q3: Suppose the cities Abat and Boto are 80 miles apart and I travel from Abat to Boto at 40 mph and from Boto to Abat at 20 mph. What is my average speed for the trip?
I should point out that I am now a units freak since my engineering husband always insisted that I include units when talking to him. In becoming such, I have learn to avoid many traps such as answering 30 mph to Q3.
Average speed = total distance/total time. Notice that the unit is correct!
A1: The total distance is: 2 hrs*40 mph+2 hrs*20 mph= 120 miles. The total time is: 2 hrs+2 hrs=4 hrs.
average speed = 120 miles/4hrs = 30 mph
A2: The total distance is: 2 hrs*40 mph+4 hrs*20 mph= 160 miles. The total time is: 2 hrs+4 hrs = 6 hrs.
average speed = 160 miles/6 hrs = 26.7 mph
A3: The total distance is: 80 miles+80 miles=160 miles.

The total time must be calculated and is: 80 miles/40 mph + 80 miles/20 mph =2 hrs+4 hrs=6 hrs.
So this is the same problem as Q2. I drive twice as long a time coming back at
20 mph as going at 40 mph .
average speed = 26.7 mph

Resource: These questions arose when I was thinking about the 2nd comment to my last blog about harmonic averages (thank-you Math Maker!) and so I looked around for more information at wikipedia (more about this to come in future blogs).

25 April 2009

Goodie for April 2009

Filed under: 8-12,algebra,education,math — admin @ 11:17 am

I loved this question. You can ask it in almost any class.
If Johnny has a 82% average for the 1st 9weeks and a 75% average for the 2nd 9weeks, what grade would he have to get on the final to receive 80% semester grade in this class.  The grades are weighted as follows: each 9 weeks average counts 40% and the final test counts 20%.
Source: MathForum@Drexel

How did I find it? I was working on a Build your Own Simulator Kit using the freeware GeoGebra. To build the simulator, the student must make the ball go from point A to point B as s goes from 0 to 1. How to explain that this is: P=A*(1-s)+B*s ?  You can see here. Then a colleague of mine said “This is weighted averages and can be used in algebra, probability and geometry and can be expanded to n weights. Too bad we don’t talk about that anymore. Those problems are really rich.” So I looked around to see what he was talking about and found this problem.  There is so much logic and usefulness in this problem – but not really any kind of special mathematics. Too bad we label it with such an awful name: weighted averages.  It is just a good question.

1. Check that the grading system makes sense: 2 × 9 week  + 1 × final test = 2 × 40% +1 × 20% = 100%. Right.

2. Let x=grade on final test.
Each 9 week grade counts 40% and final test 20% so we have:  82% × 40% + 79% ×40% + x ×20%
What does this expression equal? Well, we want an 80% total average at the end.
But we cannot write Expression=80% because it is obvious that we need another “%”.
(This is actually the hard part.)  We have not used “at the end“. What does “at the end” mean?  It means 100%.

So our equation is:    82% × 40% + 79% ×40% + x × 20% = 80% × 100%.

Cancel all percentages and solve to get  x=79%.

8 March 2009

Baddie of the Month – Teaching complex numbers with the quadratic formula

Filed under: 8-12,algebra,applets,education,K-12,math — Tags: , , , — admin @ 12:14 am

Goodie: “A technique/question that can be applied in many places and teaches thinking.”

Baddie: “A technique/question that is a waste of good teaching and learning-to-think-and-do-math time.”

March 2009 Baddie of the MonthTeaching complex numbers with the quadratic formula.

Who was the dingbat who first decided to work complex numbers when teaching the quadratic formula?

And why? Because you can get complex conjugate numbers from the quadratic formula?

A car has brakes. Do we teach hydraulics to someone learning to drive a car?

Storyline: We are teaching quadratics. Everything we discuss is totally real. (In fact, we usually "fix" our problems to be with integers, but that is subject of previous rants.)

We are factoring, finding intercepts, drawing graphs in the Cartesian plane – all real numbers.

In the middle of this, we start teaching a totally different subject – namely complex numbers.

And then we go back to real numbers and real applications of quadratic functions.

Let’s face facts.

(a) Complex numbers have NO relation to quadratic functions or their applications that we will work on.

(b) Complex numbers have NO visual representation on the graph of a quadratic function*.

Ergo – complex numbers do NOT help us understand quadratics.

Conclusion: Do NOT mention complex numbers at all when teaching the quadratic formula.

Simply state that when D<0 (negative discriminant) the quadratic function has no roots and therefore does not cross the x-axis. Don’t mention "real roots". Don’t go anywhere else with this discussion at all.

STICK TO THE SUBJECT MATTER AT HAND – Quadratic functions and their applications.


This is the material in a typical textbook in the chapters for quadratic functions. (This is actually a reasonable toc. Some left me gasping for breath.)

Let’s go. We only have 2 months. No problem – we will fix everything to be integers.

  1. Here is a quadratic function y= x². Let’s make a table of points. (Hmm – I’ve only ever graphed a line. I know I can graph a line using any 2 points. What the heck are all these points?)
  2. The graph of a quadratic function is a parabola. (Hmm – So a parabola is the graph of a quadratic function?)
  3. Here is the general expression of a quadratic y=ax²+bx+c, where x and y are variables and a, b and c are constants. (Hmm – They all look like letters to me.) Also, m²-2km+k² is a quadratic. (Huh?)
  4. Let’s factor ax²+bx+c. Here are a bunch of rules. (Dang, I can’t factor this quadratic x²-3x-2. Teacher said it was because I copied wrong x²-3x+2. Do these rules work?)
    Here are some more rules. (Hmm – Why do we want to factor? What are those numbers anyway?)
  5. Let’s complete the square. Here is the plan. The point (h,k) is the vertex. (Hmm – Why is it the vertex? Why is there a minus in front of h and a plus in front of k?)
  6. Let’s graph quadratics by completing the square and transforming the graph of y=x². (Say what? You go left when? First upside down? And then stretch?)
  7. Here is the quadratic formula. We prove it using completing the square. (Wow, look at all those letters and equations. Now – square root. Plus and minus sign. Never seen that operation before – cool.)
  8. Using quadratic formula, let’s find the roots of a quadratic. (Roots? Is there a function here? Is there an equation here? Linear functions have roots?) The roots are the factors. (Hmm. Roots look easy to find. Couldn’t we just factor that way and skip all that factoring stuff?)
  9. Let’s graph a quadratic by completing the square. Now use the quadratic formula to find the roots. The roots are the x-intercepts of the function. (Hmm. Roots look easy to find. Aren’t parabolas symmetric? Why can’t I just find the vertex by going halfway between the roots and skip all that completing the square and transforming the function?)

Okay – I am sure they got all that. Let’s pause and do a totally different subject.

  1. D is called the discriminant. D can be positive, zero or negative. If D is negative, the quadratic function doesn’t have real roots. (Real roots? Are there fake roots?)
  2. If D is negative, the quadratic function has complex roots, which are complex numbers. You remember: z=x+iy. Complex roots come in pairs called complex conjugates.
    *Wait – we can make this worse. Let’s graph complex numbers and their conjugates in the plane. (No kidding – my son did this in the middle of learning to graph quadratics.)
    (Whoa – I thought we were talking about quadratic functions and graphing parabolas. What do I get with complex conjugates? Where do I put these on the graph? Whaaaaaaaaaat?)

Now back to quadratics. Back to the reals – are we totally confused yet?

  1. Now let’s look at applications of quadratic functions.

Related topics:

Past: February 2009 Goodie of the month – Good questions for Quadratic Equations/Functions

Past: February 2009 Baddie of the month – Teaching completing the square to graph a quadratic.

Past: January 2009 Baddie of the Month – Hand-factoring a quadratic with a≠1.

25 January 2009

Goodie of the Month – A Good Question for Algebra 1

Filed under: algebra,applets,education,ICT,math — Tags: , , , , — admin @ 2:01 am

Goodie: “A technique/question that can be applied in many places and teaches thinking.”

Baddie: “A technique/question that is a waste of good teaching and learning-to-think-and-do-math time.”

January 2009 Goodie of the MonthA Good Question for Algebra 1

Two ships are sailing in the fog and are being monitored by tracing equipment. As they come into the observer’s rectangular radar screen, one ship, the Rusty Tube, is at a point 900 mm to the right of the bottom left corner of the radar screen along the lower edge. The other ship, the Bucket of Bolts, is located at a point 100 mm above the lower left corner of that screen. One minute later, both ships’ positions have changed. The Rusty Tube has moved to a position on the screen 3 mm left and 2 mm above its previous position on the radar screen. Meanwhile, the Bucket of Bolts has moved to a position 4 mm right and 1 mm above its previous location on that screen.
Assume that both ships continue to move at a constant speed on their respective linear courses. Using graphs and equations, find out if the two ship will collide.

Why do I like this question?

  • Students can understand it and it is fun.
  • They can graph it on paper or using a graphing program.
  • It involves finding the equation of a line through 2 points (twice) – good reinforcement.

Why do I think it is a “good question”?

  1. The graph looks like every 2×2 system of linear equations they have solved in Algebra 1.
    • It looks like the boats collide at the intersection point (see below).
    • It seems like all they need to do is solve the system and be done.
    • … until you say “Where is time on the graph?”.
  2. The student can build a animated simulator that “shows time” – easily!
  3. The kids can make the boats collide – what fun!.
    • They can move the starting points until they get the boats to collide.
    • They can also adapt the simulator so that they can change the slopes and get the boats to collide. Directions here.
    • My thanks to David Cox for seeing this!
  4. You can get all kinds of mathematics out of them.
    • You can get them to calculate when each of the boats reaches the intersection point in the original question.
    • You can get them to check the math on their “colliding simulator” to see if the boats really do collide, where and when.
    • You can ask them about a 3D graph and what this would look like when the boats don’t collide and when they do.

To animate, click on the play button at bottom left of graph.

To animate manually, right-click on slider and deselect “Animation on”. Then, click and drag the point on the slider.

Sorry, the GeoGebra Applet could not be started. Please make sure that Java 1.4.2 (or later) is installed and active in your browser (Click here to install Java now)

Source: I found this question asked on My webpage for this question is:

Powered by WordPress